来个极坐标积分
syms rho theta
f = rho;
s = int(int(f,rho,0,2*(1-sin(theta))), theta,0,2*pi)
得到
s =
6*pi
假设要蒙特卡洛方法:
n = 100000;
x = 8*rand(n,1)-4;
y = 8*rand(n,1)-4;
theta = atan2(y,x);
rho = sqrt(x.^2+y.^2);
P = sum(rho<=2*(1-sin(theta)))/n; %概率
s = P*(8*8)
结果是随机的
s =
19.0688
有帮助望采纳哟,谢谢啦