//求x的n次方
#include<stdio.h>
#include<math.h>
int main()
{
int n;
double x,Root;
double calc_pow(double x,int n);
printf("Enter x:");
scanf("%d",&x);
printf("Enter n:");
scanf("%lf",&n);
printf("Root = %lf\n",calc_pow(x,n));
return 0;
}
double calc_pow(double x,int n)
{
if(n<=1)
return x;
else
return x*calc_pow(x,n-1);
}
x为什么用%d输入