使用python3 在leedcode中完成括号匹配

class Solution:
    def isValid(self, s: str) -> bool:
        match = {'}':'{',')':'(',']':'['}
        stack = []
        if len(s)%2 == 1:
            return False
        for ch in s:
            
            if ch in ['(','[','{']:
                stack.append(ch)
                return True
            else:       #ch in {')','}',']'}
                if len(stack) <=0: 
                    return False
                elif stack[-1] == match[ch]:
                    return stack.pop()
                else:
                    return False  
        if len(stack)==0:
            return True
        else:
            return False
        

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