led点阵为什么只显示最后一行 不轮流显示数字

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    #include <reg51.h>
unsigned char code  tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
                    //列线值
unsigned char code digittab[10][8]={
{0x00,0x00,0x3e,0x41,0x41,0x41,0x3e,0x00}, //0的行值
{0x00,0x00,0x00,0x00,0x21,0x7f,0x01,0x00}, //1
{0x00,0x00,0x27,0x45,0x45,0x45,0x39,0x00}, //2
{0x00,0x00,0x22,0x49,0x49,0x49,0x36,0x00}, //3
{0x00,0x00,0x0c,0x14,0x24,0x7f,0x04,0x00}, //4
{0x00,0x00,0x72,0x51,0x51,0x51,0x4e,0x00}, //5
{0x00,0x00,0x3e,0x49,0x49,0x49,0x26,0x00}, //6
{0x00,0x00,0x40,0x40,0x40,0x4f,0x70,0x00}, //7
{0x00,0x00,0x36,0x49,0x49,0x49,0x36,0x00}, //8
{0x00,0x00,0x32,0x49,0x49,0x49,0x3e,0x00} //9
};
  unsigned char lie;    //定义列变量 
unsigned char shu;     //定义要显示数字的顺序变量
 void delay()

{
unsigned char i,j;
for(i=0;i<10;i++)
for(j=0;j<200;j++);
}
void main()
{
lie=0;
shu=0;
while(1)
{
P3=tab[lie]; //送列值
P0=digittab[shu][lie]; //送行值
lie++; //列值加1
if(lie==8)
{lie=0; //8列扫描完，列值归0
delay();
shu++; //换下一个数字
if(shu==10)
shu=0; //0～9显示完，再从0开始
}
}
}

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