Mathematica求解三方演化博弈模型的均衡解

F(x)= x(1－x)[C(yz－1)+y(1－z)(P+P1)]=0
F(y)= y(1－y){z(C2－S)+(1－z)[R－C2－x(S1+P2+P1)] +x(zC1－G1)－E1}=0
F(z)= z(1－z){－y[R(i－r1)－C3]+(1－y)[E2+x(G2－C)] +(1+xy－y)(S2+P)+x(P3+C)－R2+C3}=0