python pandasql库操作 sql 语句，我语句里用了求余 mod()函数，报错，提示我 sqlite3.OperationalError: no such function: mod

python pandasql库操作 sql 语句，我在查询语句里用了求余 mod()函数
在 mysql 中运行没有报错，可以查询到
语句在 Python 中报错，提示我 sqlite3.OperationalError: no such function: mod
查询语句代码附下

select * from tables WHERE 
            mod(( 
 
                substr(A5,1,1)*7+ 
 
                substr(A5,2,1)*9+ 
 
                substr(A5,3,1)*10+ 
 
                substr(A5,4,1)*5+ 
 
                substr(A5,5,1)*8+ 
 
                substr(A5,6,1)*4+ 
 
                substr(A5,7,1)*2+ 
 
                substr(A5,8,1)*1+ 
 
                substr(A5,9,1)*6+ 
 
                substr(A5,10,1)*3+ 
 
                substr(A5,11,1)*7+ 
 
                substr(A5,12,1)*9+ 
 
                substr(A5,13,1)*10+ 
 
                substr(A5,14,1)*5+ 
 
                substr(A5,15,1)*8+ 
 
                substr(A5,16,1)*4+ 
 
                substr(A5,17,1)*2 
 
            ),11) 
 
            <> 
                        ( 
 
            case
 
                when substr(A5,18,1)='1' then '0'
 
                when substr(A5,18,1)='0' then '1'
 
                when substr(A5,18,1) in ('X','x') then '2'
 
                when substr(A5,18,1)='9' then '3'
 
                when substr(A5,18,1)='8' then '4'
 
                when substr(A5,18,1)='7' then '5'
 
                when substr(A5,18,1)='6' then '6'
 
                when substr(A5,18,1)='5' then '7'
 
                when substr(A5,18,1)='4' then '8'
 
                when substr(A5,18,1)='3' then '9'
 
                when substr(A5,18,1)='2' then '10'
 
            end
 
            )

mod不是函数，不能使用括号。