你好,比如第三题
n = 1; s = 1; ds = 1; f = n; while (ds>1e-5) s = s+ds; n=n+1; f = f*n; ds = 1/f; end fprintf('最小项数%d, 实际误差%f',n,(s-exp(1))/exp(1))
结果:最小项数9, 实际误差-0.000001