#include<stdio.h>
double f(double x,int n)
{if(n==0)return 1;
else if(n>0)return x*f(x,n-1);
else return f(x,n+1)/x;
}
int main()
{ double x;
int n;
scanf("%lf%dc",&x,&n);
if(x==0)
{
if(n!=0)
printf("%lg^%d=0\n",x,n);
else
printf("error!");
}
else
printf("%lg^%d=%lg\n",x,n,f(x,n));
getch();
return 0;
}
#include<stdio.h>
long sum(int n)
{
return((1+n)*n/2);
}
int main()
{
int n;
printf("n=");
scanf("%d",&n);
printf("sum=%d\n",sum(n));
return(0);
}
#include<stdio.h>
int runnian(int a);
int tian(int b);
int main()
{
int a,b,c,d;
scanf("%d %d %d",&a,&b,&c);
d=tian(b);
printf("该天是本年的第%d天",d+c);
return 0;
}
int runnian(int a)
{
if((a%4= =0 && a%100!=0) ||(a%400= =0))
return 1;
else
return 0;
}
int tian(int b)//求前面已经过去了的月份的天数，例如5月9日，则求4+3+2+1月份天数
{
int i,j,a;
j=runnian(a);
switch (b-1)
{
case 11: i+=30;
case 10: i+=31;
case 9: i+=31;
case 8: i+=30;
case 7: i+=31;
case 6: i+=30;
case 5: i+=31;
case 4: i+=30;
case 3: i+=31;
case 2:
{
if(j==1)
i+=29;
else
i+=28;
};
case 1: i+=31;
default:
break;
}
return i;
}