输入整数n,编程计算sum=1!+2!+.....+n!
int a=0,sum=0,n=12;
for(int i=1;i<=n;i++)
{
a*=i;
sum+=a;
}
#include <stdio.h>
unsigned long factorial(int n)//求阶乘
{
int sum = 1;
n&&(sum = n*factorial(n-1));//递归到0时,利用与的"短路"性质,递归返回sum=1
return sum;
}
int main(int argc ,char **argv[])
{
int i = 0;
int n = 0;
int sum = 0;
printf("please enter the n :");
scanf("%d",&n);
for( i = 1 ; i <= n ; i++) //32位最大十亿位,n要小于15,否则溢出
sum += factorial(i);
printf("sum=1!+2!+......+%d!=%d\n",n,sum);
return 0;
}
n=3
n=4
n=5
希望采纳