如这样一个数组:
positionatom1 =
[ ' 0 0 14.138181183815000 La';
' 0 0 3.410323816185000 O ';
' 2.014519000000000 2.014519000000000 11.667720198420000 Cl';
' 2.014519000000000 2.014519000000000 5.880784801580000 As';
' 4.029038000000000 0 14.138181183815000 Fe'];
你好,用fprintf和%s就行
positionatom1 =[ ' 0 0 14.138181183815000 La';
' 0 0 3.410323816185000 O ';
' 2.014519000000000 2.014519000000000 11.667720198420000 Cl';
' 2.014519000000000 2.014519000000000 5.880784801580000 As';
' 4.029038000000000 0 14.138181183815000 Fe'];
fid = fopen('positionatom1.txt','wt');
for i =1:size(positionatom1,1)
fprintf(fid, '%s\n',positionatom1(i,:));
end