萌新,想问问程序中关于++--的五个式子从左边开始计算,结果为什么不是45555?感谢您的帮助。
#include <iostream>
#include <algorithm>
using namespace std;
#pragma warning(disable:4996)
int main() {
00F91810 push ebp
00F91811 mov ebp,esp
00F91813 sub esp,0D4h
00F91819 push ebx
00F9181A push esi
00F9181B push edi
00F9181C lea edi,[ebp-0D4h]
00F91822 mov ecx,35h
00F91827 mov eax,0CCCCCCCCh
00F9182C rep stos dword ptr es:[edi]
int i = 5;
00F9182E mov dword ptr [i],5
printf("%d%d%d%d%d", --i, ++i, i++, --i, i++);
00F91835 mov eax,dword ptr [i]
00F91838 mov dword ptr [ebp-0D0h],eax
00F9183E mov ecx,dword ptr [i]
00F91841 add ecx,1
00F91844 mov dword ptr [i],ecx
00F91847 mov edx,dword ptr [i]
00F9184A sub edx,1
00F9184D mov dword ptr [i],edx
00F91850 mov eax,dword ptr [i]
00F91853 mov dword ptr [ebp-0D4h],eax
00F91859 mov ecx,dword ptr [i]
00F9185C add ecx,1
00F9185F mov dword ptr [i],ecx
00F91862 mov edx,dword ptr [i]
00F91865 add edx,1
00F91868 mov dword ptr [i],edx
00F9186B mov eax,dword ptr [i]
00F9186E sub eax,1
00F91871 mov dword ptr [i],eax
00F91874 mov ecx,dword ptr [ebp-0D0h]
00F9187A push ecx
00F9187B mov edx,dword ptr [i]
00F9187E push edx
00F9187F mov eax,dword ptr [ebp-0D4h]
00F91885 push eax
00F91886 mov ecx,dword ptr [i]
00F91889 push ecx
00F9188A mov edx,dword ptr [i]
00F9188D push edx
00F9188E push offset string "%d%d%d%d%d" (0F96B30h)
00F91893 call _printf (0F91320h)
00F91898 add esp,18h
}
Debug一顿就知道了。