有朋友会吗 求解 用c语言

解

#include <stdio.h>
#include <math.h>
int main(void)
{
float a, b, c, de;
scanf("%f %f %f", &a, &b, &c);
de = b * b - 4 * a * c;
if (a == 0 && b == 0)
{
if (c != 0)
printf("Not An Equation");
else
printf("Zero Equation");
}
else if (a == 0 && b != 0)
{
if (c != 0)
printf("%.2f", -c / b);
else
printf("%.2f", 0);
}
else if (de > 0)
printf("%.2f\n%.2f", (-b + sqrt(de)) / (2 * a), (-b - sqrt(de)) / (2 * a));
else if (de == 0)
printf("%.2f", -b / (2 * a));
else
{
if (-b / (2 * a) != 0)
{
printf("%.2f+%.2fi\n", -b / (2 * a), sqrt(-de) / (2 * a));
printf("%.2f%.2fi\n", -b / (2 * a), -sqrt(-de) / (2 * a));
}
else
{
printf("0.00+%.2fi\n", sqrt(-de) / (2 * a));
printf("0.00%.2fi\n", -sqrt(-de) / (2 * a));
}
}

return 0;

}