#include <stdio.h>
int main()
{
int N,i,flag=1;
double sum = 0;
scanf("%d",&N);
for(i=1;i<=N;i++)
{
sum += flag*1.0/(2*i-1);
flag *=-1;
}
printf("%.10lf",sum*4);
return 0;
}
a=0
sum=0
N=eval(input("请输入N:"))
for n in range(1,N):
if n%2!=0:
a+=1
if a%2==0:
n=-n
sum+=1/n
print('{:.10f}'.format(sum*4))