对这题目没有思路,求大佬解疑。
#include "stdio.h"
void main(){
int month,days;
printf("请输入2008年的月份:");
scanf("%d",&month);
switch(month){
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
days=31;
break;
case 4:
case 6:
case 9:
case 11:
days=30;
break;
case 2:
days=29;
break;
default:
printf("请输入1~12的有效月份\n");
break;
}
if(month>=1 && month<=12)
printf("2008年的%d月有%d天\n",month,days);
}
代码如下,如有帮助,请帮忙采纳一下,谢谢。
#include <stdio.h>
int main()
{
int year,mon,day;
int i,sum = 0;
int arr;
scanf("%d,%d,%d",&year,&mon,&day);
for (i=1;i<mon;i++)
{
switch(i)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
arr = 31;break;
case 4:
case 6:
case 9:
case 11:
arr = 30;break;
case 2:
if(year%4==0 && year%100 != 0 || year%400 == 0)
arr = 29;
else
arr =28;
break;
}
sum += arr;
}
sum += day;
printf("%d年%d月%d日是今年的第%d天\n",year,mon,day,sum);
return 0;
}