编程序,要求输入任意n值,有1-1/2+2/3+…+n-1/n
#include<stdio.h>
int main()
{
double a=1,b=0,i,sum=0,n,k=1;
printf("请输入n:");
scanf("%lf",&n);
for(i=2;i<=n;i++)
{
a=a+1;
b=b+1;
k=-k;
sum=sum+k*(b/a);
}
printf("1-1/2+2/3-3/4...(n-1)/n =:");
printf("%lf",sum);
return 0;
}
-是什么鬼?