尽可能简单的用Java完成火车票时间问题

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class MyTime{
    private int day;
    private int hour;
    private int minute;

    public MyTime(){
        this.hour=this.minute=this.minute=0;
    }

    public MyTime(int hour, int minute) {
        this.hour = hour;
        this.minute = minute;
    }

    //能计算两个时间的和
    public MyTime timeAdd(MyTime s) {
        MyTime result = new MyTime();
        int d,h,m;
        m = s.minute + this.minute;
        h = s.hour + this.hour + m / 60;
        d = s.day + this.day + h / 24;
        result.day = d;
        result.hour = h %24;
        result.minute = m % 60;
        return result;
    }

    //比较两个时间是否相同
    public boolean eguals(MyTime s){
        return this.day==s.day&&this.hour==s.hour&&this.minute==s.minute;
    }

    public String toCNString() {//按中文形式转化时间
     if(day>0)
        return  day+"天"+hour+"小时"+minute+"分钟";
     else
         return  hour+"小时"+minute+"分钟";
    }

    @Override
    public String toString() {
        if(day>0)
            return "+" + day+"天 "+hour+":"+minute;
        else
            return hour+":"+minute;
    }
}

public class Solution {
    public static void main(String[]args){
        /*
        在main方法中创建至少三组起始时间和运行时间，计算到达时间。
        输出效果例如：
        起始时间 运行时间 到达时间
        20:12 35小时10分钟 +2天07:22
         */
        MyTime m1, m2,m3;

        m1 = new MyTime(20,12);
        m2 = new MyTime(35, 10);
        m3 = m1.timeAdd(m2);
        System.out.println("起始时间\t运行时间\t到达时间");
        System.out.println(m1+" "+m2.toCNString()+" "+m3);


        m1 = new MyTime(20,12);
        m2 = new MyTime(50, 10);
        m3 = m1.timeAdd(m2);
        System.out.println("起始时间\t运行时间\t到达时间");
        System.out.println(m1+" "+m2.toCNString()+" "+m3);

        m1 = new MyTime(20,12);
        m2 = new MyTime(2, 10);
        m3 = m1.timeAdd(m2);
        System.out.println("起始时间\t运行时间\t到达时间");
        System.out.println(m1+" "+m2.toCNString()+" "+m3);

    }
}

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