Consider A Game In Which There Is A Prize Worth 230.各位可不可以帮我解这一题呀？太难了

各位可不可以帮我解这一题呀？ 太难了

Consider a game in which there is a prize worth $20. There are three contestants, Mary, Tom, and Tina. Each can buy a ticket worth $10 or $20 or not buy a ticket at all. They make these choices simultaneously and dependently. Then, knowing the ticket-purchase decisions, the game organizer awards the prize. If no one has bought a ticket, the prize is not awarded. Otherwise, the prize is awarded to the buyer of the highest-cost ticket if there is only one such player or is split equally between two or three if there are ties among the highest-cost ticket buyers. Show this game in strategic form, using Larry as the row player, Curly as the column player, and Moe as the page player.

1. Show this game in matrix form.
2. what are the three player's best responses to others' decisions?
3. Find all pure-strategy Nash equilibria (hint: Totally, there are six Nash Equilibria)

// caimi8.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"

#include <vector>
#include <string>
using namespace std;


void JudgeVec(vector<int> vec,vector<int>& vecRE)
{
    if (vec[0]>vec[1] && vec[0]>vec[2]) // 0位置胜出
    {
        vecRE.push_back(0);
    }
    else if (vec[1]>vec[0] && vec[1]>vec[2]) // 1位置胜出
    {
        vecRE.push_back(1);
    }
    else if (vec[2]>vec[0] && vec[2]>vec[1]) // 2位置胜出
    {
        vecRE.push_back(2);
    }
    else if (vec[0] == vec[1] && vec[0] == vec[2] && vec[0] == 0)
    {
        if (vec[0] == 0) // 都没出钱
        {

        }
    }
    else if (vec[0] == vec[1] && vec[0] > vec[2] && vec[0] != 0)
    {
        vecRE.push_back(0);
        vecRE.push_back(1);
    }
    else if (vec[0] == vec[2] && vec[0] > vec[1] && vec[0] != 0)
    {
        vecRE.push_back(0);
        vecRE.push_back(2);
    }
    else if (vec[1] == vec[2] && vec[1] > vec[0] && vec[1] != 0)
    {
        vecRE.push_back(1);
        vecRE.push_back(2);
    }
    else if (vec[0] == vec[1] && vec[0] == vec[2])
    {
        if (vec[0] != 0) // 都出钱 平均分
        {
            vecRE.push_back(0);
            vecRE.push_back(1);
            vecRE.push_back(2);
        }

    }
}



int _tmain(int argc, _TCHAR* argv[])
{
    vector<string> vec1;
    vec1.push_back("\\");
    vec1.push_back("Mary");
    vec1.push_back("Tom");
    vec1.push_back("Tina");
    vec1.push_back("result");
    // 价格
    vector<int> vecPrices = {0,10,20};

    int length = 3 * 3 * 3;
    vector<vector<int>> vec2;
    vec2.resize(length, vector<int>(3, 0));
    for (size_t i = 0; i < length; i++)
    {
        for (size_t j = 1; j <=3; j++)
        {
            int iTempGe = 0;
            if (j==1)
            {
                iTempGe = i % 3;
            }
            else
            {
                iTempGe = (int)(i / pow(3, j - 1)) % (int)pow(3, j - 1);
            }
            if (iTempGe >= 10)
            {
                iTempGe = iTempGe % 10;
            }
            vec2[i][j-1] = vecPrices[iTempGe];

            int a = 0;
        }
    }


    // 打印标题
    printf(" %s", vec1[0].c_str());
    printf("     %s", vec1[1].c_str());
    printf("   %s", vec1[2].c_str());
    printf("    %s", vec1[3].c_str());
    printf("    %s", vec1[4].c_str());

    printf("\n");

    for (size_t i = 0; i < length; i++)
    {
        printf("%2d", i);
        for (size_t j = 1; j <= 3; j++)
        {
            int iWri = vec2[i][j - 1];

            if (iWri>9)
            {
                printf("     %d", iWri);
            }
            else
            {
                printf("      %d", iWri);
            }
        }
        vector<int> vectempJudge;
        JudgeVec(vec2[i], vectempJudge);
        printf("      ");
        if (vectempJudge.size() == 1)
        {
            printf("%s一人得到票", vec1[vectempJudge[0]+1].c_str());
        }
        if (vectempJudge.size() == 2)
        {
            printf("%s和%s两人得到票", vec1[vectempJudge[0] + 1].c_str(), vec1[vectempJudge[1] + 1].c_str());
        }
        if (vectempJudge.size() == 3)
        {
            printf("%s，%s和%s三人得到票", vec1[vectempJudge[0] + 1].c_str(),
                vec1[vectempJudge[1] + 1].c_str(),
                vec1[vectempJudge[2] + 1].c_str());
        }
        if (vectempJudge.size() == 0)
        {
            printf("无得到票");
        }

        printf("\n");
    }


    _tsystem(L"pause");


    return 0;
}