python中 利用递归求1-1/2+1/3-....+1/99-1/100+1/(n-1)-1/n
def func(n): ret = 0 if n == 1: return 1 if (n % 2) == 0: ret = func(n - 1) - 1 / n else: ret = func(n - 1) + 1 / n return ret func(4)