c++计算级数12+23+34+.....+n(n+1)+...前n項的和。输入只有一组数据,从键盘输入n的值,输出前n項的和。
#include "stdio.h"
void main()
{
int n;
int i;
int sum = 0;
scanf("%d",&n);
for(i=1;i<=n;i++){
sum += i*(i+1);
}
printf("sum=%d\n",sum);
}
#include <iostream>
using namespace std;
int main(int argc, char const *argv[])
{
int n;
long long int sum = 0;
cin >> n;
for (int i = 0; i < n; i++)
{
sum += (i + 1) * (i + 2);
}
cout << sum << endl;
return 0;
}
#include <iostream>
using namespace std;
int main()
{
int n;
int i;
long long s = 0;
cin >> n;
for (i=1;i<=n;i++)
{
s += i*(i+1);
}
cout << s << endl;
return 0;
}