C语言问题，交换 64 位值的位对 Swap Pairs of Bits of a 64-bit Value

望各位帮忙看看，现在就想要答案，蟹蟹各位潜水专家，感谢解答，感谢回答，感谢解答。在“PUT YOUR CODE HERE”写内容，前面内容不要改动，按照要求来写。

// swap pairs of bits of a 64-bit value, using bitwise operators

#include <assert.h>
#include <stdint.h>
#include <stdlib.h>

// return value with pairs of bits swapped
uint64_t bit_swap(uint64_t value) {
    // PUT YOUR CODE HERE

    return 42;
}

// swap pairs of bits of a 64-bit value, using bitwise operators
#include <assert.h>
#include <stdint.h>
#include <stdlib.h>
// return value with pairs of bits swapped
uint64_t bit_swap(uint64_t value) {
    uint64_t data = 0;
    int a,b,m=0;
    for(int i=0;i<32;i++)
    {
        a = value&1;
        value = value>>1;
        b = value&1;
        value = value>>1;
        m+=2;
        if(b>0)
            data |= (b<<m-2);
        if(a>0)
            data |= (a<<m-1);
    }
    return data;
}

// swap pairs of bits of a 64-bit value, using bitwise operators
#include <assert.h>
#include <stdint.h>
#include <stdlib.h>
#include<stdio.h>
// return value with pairs of bits swapped
uint64_t bit_swap(uint64_t value)
{
    uint64_t a = (uint64_t)0x55555555555555555, b = (uint64_t)0xaaaaaaaaaaaaaaaa;
    // printf("%llx\n", value);
    // printf("%llx\n", a);
    // printf("%llx\n", b);
    a = value & a;
    // printf("%llx\n", a);
    b = value & b;
    // printf("%llx\n", b);
    return ((a << 1) | (b >> 1));
}
int main(int argc, char const *argv[])
{
    printf("%llx\n", bit_swap((uint64_t)0x1111111111111111));
    printf("%llx\n", bit_swap((uint64_t)0x1111888855553333));
    return 0;
}