RequestBody body = RequestBody.create(MediaType.parse("text/xml;charset=UTF-8"), soapRequestData);
Request request = new Request.Builder()
.url("https:api.mch.weixin.qq.com/mmpaymkttransfers/sendredpack")
.post(body)
.build();
//为http请求设置证书
SSLSocketFactory socketFactory = getSSL().getSocketFactory();
X509TrustManager x509TrustManager = Platform.get().trustManager(socketFactory);
OkHttpClient okHttpClient = new OkHttpClient.Builder().sslSocketFactory(socketFactory, x509TrustManager).build();
// 得到输出内容
Response response = okHttpClient.newCall(request).execute();
String content = response.body().string();
我想把url换成本地的127.0.0.1,编写一个运行在Tomcat的代码,响应上面那个请求并返回参数,请问该怎么写啊?