js问题,关于跟随鼠标一串的效果为什么我的代码会报错?

<!DOCTYPE html>
<html lang="en">
<head>
      <meta charset="UTF-8">
      <meta name="viewport" content="width=device-width, initial-scale=1.0">
      <title>Document</title>
      <style>
            div{width: 10px;height: 10px;background-color: red;margin-top: 10px;position: absolute;}
      </style>
      <script>
      window.onload = function(){
            var divs = document.getElementsByTagName("div");
            
                  document.onmousemove = function(ev){
                        var e = ev || window.event;
                        divs[0].style.left = e.clientX + "px";
                        divs[0].style.top = e.clientY + "px";
                        for(var i = 0;i < divs.length; i--){
                              divs[i + 1].style.left = divs[i].offsetLeft + "px";
                              divs[i + 1].style.top = divs[i].offsetTop + "px";
                        }
                        
                  }
            
      }
</script>
</head>
<body>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
      <div></div>
</body>
</html>

这是我的代码,为什么divs[i + 1].style.left = divs[i].offsetLeft + "px";会报错?而下面这个就不会?


 <script>
            window.onload = function(){
                  var divs = document.getElementsByTagName("div");
                        document.onmousemove = function(ev){
                              var e = ev || window.event;
                              
                              for(var i = divs.length - 1; i > 0;  i--){
                                    divs[i].style.left = divs[i - 1].offsetLeft + "px";
                                    divs[i].style.top = divs[i - 1].offsetTop + "px";
                              }
                              divs[0].style.left = e.clientX + "px";
                              divs[0].style.top = e.clientY + "px";
                              
                        }
                  
            }
      </script>