完善下列程序,实现对一玩家手中的13张牌按照从小到大排序后输出。
#include <stdio.h>
typedef struct
{ int suit; // 花色 1..4 1~4分别代表梅花,方块,红桃,黑桃
int rank; // 牌点 2..14 其中11~14分别代表J,Q,K,A
} Poker;
void SortCard(Poker cards[], int n)
{ int i,j,p; Poker t;
/* 请在此处补上部分代码,实现程序的功能 */
}
void PrintCard(Poker cards[], int n)
{ char suit[][5]={"","梅花","方块","红桃","黑桃"};
char rank[]="JQKA";
int i;
/* 请在此处补上部分代码,实现程序的功能 */
}
int main()
{ Poker player[13]={ {3,11},{4,3},{2,9},{3,8},{3,14},{1,10},
{1,7},{2,3},{3,6},{1,12},{4,13},{4,6},{2,5}};
printf("发牌后玩家手中的13张牌:\n");
PrintCard(player,13);
SortCard(player,13);
printf("\n理牌后玩家手中的13张牌:\n");
PrintCard(player,13);
getchar();
return 0;
}
大概这种感觉?
#include <stdio.h>
typedef struct
{
int suit; // 花色 1..4 1~4分别代表梅花,方块,红桃,黑桃
int rank; // 牌点 2..14 其中11~14分别代表J,Q,K,A
} Poker;
int compare(Poker card1, Poker card2)
{
if (card1.suit > card2.suit)
{
return 1;
}
else if (card1.suit < card2.suit)
{
return 0;
}
else
{
if (card1.rank > card2.rank)
return 1;
else
return 0;
}
}
void SortCard(Poker cards[], int n)
{
Poker t;
for (int i = 0; i < n - 1; i++)
{
for (int j = 0; j < n - 1 - i; j++)
{
if (compare(cards[j], cards[j + 1]))
{
t = cards[j + 1];
cards[j + 1] = cards[j];
cards[j] = t;
}
}
}
}
void PrintCard(Poker cards[], int n)
{
char suit[][5] = {"", "梅花", "方块", "红桃", "黑桃"};
char rank[] = "JQKA";
for (int i = 0; i < n; i++)
{
printf("%s%c\t", suit[cards[i].suit], cards[i].rank > 10 ? rank[cards[i].rank - 11] : (cards[i].rank == 10 ? 'T' : cards[i].rank + '0'));
}
}
int main()
{
Poker player[13] = {{3, 11}, {4, 3}, {2, 9}, {3, 8}, {3, 14}, {1, 10}, {1, 7}, {2, 3}, {3, 6}, {1, 12}, {4, 13}, {4, 6}, {2, 5}};
printf("发牌后玩家手中的13张牌:\n");
PrintCard(player, 13);
SortCard(player, 13);
printf("\n理牌后玩家手中的13张牌:\n");
PrintCard(player, 13);
// getchar();
return 0;
}
你得说一下排序的规则,因为涉及到点数和花色两种可排序值啊。从大到校,还是从小到大