Description
输入年和月,判断该月有几天?
Input
输入年和月,格式为年\月。
Output
输出该月的天数。
#include <stdio.h>
#include <stdlib.h>
int main()
{
int y,m;
scanf("%d\%d",&y,&m);
if(y%400==0||(y%100!=0&&y%4==0))
{
switch(m)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:printf("31");break;
case 2:printf("28");break;
case 4:
case 6:
case 9:
case 11:printf("30");break;
}
}
else
{
switch(m)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:printf("31");break;
case 2:printf("29");break;
case 4:
case 6:
case 9:
case 11:printf("30");break;
}
}
return 0;
}
输出格式不知道题目有没有要求,就按题主写的格式。修改如下,供参考:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int y,m,flg = 0;
scanf("%d\\%d",&y,&m);// \是转义符
if((y%4==0 && y%100!=0) || (y%400==0))
flg = 1; //修改
switch(m){
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:printf("31");break;
case 2:
if(flg) printf("29");//修改
else printf("28");
break;
case 4:
case 6:
case 9:
case 11:printf("30");break;
}
//else
//{
//switch(m)
//{
//case 1:
//case 3:
//case 5:
//case 7:
//case 8:
//case 10:
//case 12:printf("31");break;
//case 2:printf("29");break;
//case 4:
//case 6:
//case 9:
//case 11:printf("30");break;
//}
//}
return 0;
}
你可以先说说问题所在