有朋友能敲出这道题的答案吗，python的。。

假如有列表：

```books = [{"name":"C#", "price":23.7, "store":"amaing"},
　　            {"name":"ASP.NET", "price":44.5, "store":"amaing"},
　　            {"name":"C#", "price":24.7, "store":"dd"},
　　            {"name":"ASP.NET", "price":45.7, "store":"dd"},
　　            {"name":"C#", "price":26.7, "store":"xh"},
　　            {"name":"ASP.NET", "price":55.7, "store":"xh"}]  _
求：
1、《ASP.NET》价格最便宜的店：
2、求列表中有哪几本书：
3、求每本书的平均价格：

如果有帮助的话，请点击右上角【采纳】按钮，支持一下！！

books = [{"name":"C#", "price":23.7, "store":"amaing"},{"name":"ASP.NET", "price":44.5, "store":"amaing"},{"name":"C#", "price":24.7, "store":"dd"},{"name":"ASP.NET", "price":45.7, "store":"dd"},{"name":"C#", "price":26.7, "store":"xh"},{"name":"ASP.NET", "price":55.7, "store":"xh"}] 



# 1、《ASP.NET》价格最便宜的店：
aimbook = "ASP.NET"
price = 100
shopName = [0]
for i in range(len(books)):
    if books[i]["name"]==aimbook:
        if books[i]["price"] < price:
            price = books[i]["price"]
            shopName[0] = books[i]["store"]
print("《ASP.NET》价格最便宜的店：",shopName,"价格为：",price)
print()

# 2、求列表中有哪几本书：
bookList = []
for i in range(len(books)):
    if books[i]["name"] not in bookList:
        bookList.append(books[i]["name"])
print("列表中有:",bookList)
print()

# 3、求每本书的平均价格：
priceList = [0,0]
count = [ 0,0]
for i in range(len(books)):
    if books[i]["name"]=="C#":
        priceList[0] = priceList[0] + books[i]["price"]
        count[0] += 1
    elif books[i]["name"]=="ASP.NET":
        priceList[1] = priceList[1] + books[i]["price"]
        count[1] += 1
        
print("《C#》的平均价格为：",priceList[0]/count[0])
print("《ASP.NET》的平均价格为：",priceList[1]/count[1])
        

books = [{"name":"C#", "price":23.7, "store":"amaing"},
{"name":"ASP.NET", "price":44.5, "store":"amaing"},
{"name":"C#", "price":24.7, "store":"dd"},
{"name":"ASP.NET", "price":45.7, "store":"dd"},
{"name":"C#", "price":26.7, "store":"xh"},
{"name":"ASP.NET", "price":55.7, "store":"xh"}]
storename=min([b for b in books if b['name']=="ASP.NET"],key=lambda b:b['price'])["store"]
bookenames=list(set(b['name'] for b in books))

print(storename)
print(bookenames)

你题目的解答代码如下：（如有帮助，望采纳！谢谢! 点击我这个回答右上方的【采纳】按钮）

books = [{"name":"C#", "price":23.7, "store":"amaing"},
{"name":"ASP.NET", "price":44.5, "store":"amaing"},
{"name":"C#", "price":24.7, "store":"dd"},
{"name":"ASP.NET", "price":45.7, "store":"dd"},
{"name":"C#", "price":26.7, "store":"xh"},
{"name":"ASP.NET", "price":55.7, "store":"xh"}
]
minv = 9999999
d = {}
for v in books:
    if v["name"]=="ASP.NET" and v["price"]<minv:
        minv = v["price"]
        store = v["store"]
    t = d.setdefault(v["name"],[0,0])
    t[0] += v["price"]
    t[1] += 1

print("《ASP.NET》价格最便宜的店是：",store)
print("列表中有哪几本书：",*d)
for k,v in d.items():
    print(k,"书的平均价格：",v[0]/v[1])