你好!答案仅供参考
n=10;
A = flip(eye(n));
A([1,end],:)=1;
disp(A)
结果:
1 1 1 1 1 1 1 1 1 1
0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 1 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 0
1 1 1 1 1 1 1 1 1 1