参考如下,如有帮助,请帮忙采纳一下,谢谢。
#include <stdio.h>
void fun(char* s)
{
int i=0,j=0;
int len =0; //总长度
int ma ; //最后的字母位置
while(s[len] != '\0')
len++;
ma = len-1;
while(s[ma] == '*')
ma--;
while(s[i] == '*')
s[j++] = s[i++];
while(i<=ma)
{
if(s[i] != '*')
s[j++] = s[i];
i++;
}
for(i=ma+1;i<len;i++)
s[j++] = s[i];
s[j] = 0;
}
int main()
{
char s[81]={0};
gets(s);
fun(s);
printf("%s\n",s);
return 0;
}
参考代码如下:(如有帮助,望采纳!谢谢! 点击我这个回答右上方的【采纳】按钮)
#include <stdio.h>
void fun(char *a, char *h, char *p)
{
char *c=h;
while (h!=p+1){
if (*h!='*'){
*c = *h;
c++;
}
h++;
}
while (*h!='\0'){
*c = *h;
c++;
h++;
}
*c='\0';
}
int main()
{
char s[81]={0},*t,*f;
gets(s);
t=f=s;
while(*t)t++;
t--;
while(*t=='*')t--;
while(*f=='*')f++;
fun(s,f,t);
puts(s);
return 0;
}