一道python的题，救命！

输入金额，输出里得出这是几个500，几个200，几个100等等

def get_out(num_in):
key = [500, 200, 100, 50, 20, 10, 5, 2, 1]
value = [0]*len(key)
try:
num = int(num_in)
except ValueError:
print("It's not num!")
return

for i in range(len(key)):
    n, num = num/key[i], num%key[i]
    value[i] = n
value[-1] = num

out_put = str(num_in) + "$ = "
for i in range(len(key)):
    if value[i]:
    out_put += str(value[i]) + "*" + str(key[i])+"$ + "

return out_put[:-3]

简化下思维，获取输入值的百位 十位 个位 输出的时候百位加两个0，十位1个0就好了

NB，这是法语吗？
做一下if判断就好了，分别对500，200，100从大到小求除和求余

        
```python

if money/500>=1:
    n500 = meney/500
    money1 = mony%500
    if money1/200>=1:
        n200 = meney1/200
        money2 = money1%200
        if money2/100 >= 1:
            # 不断重复

```
最后获取的一系列n就是你要的了

#!/usr/bin/env python

def get_out(num_in):
try:
num = int(num_in)
except ValueError:
print("It's not num!")
return

n_500, num = num/500, num%500
n_200, num = num/200, num%200
n_100, num = num/100, num%100
n_50, num = num/50, num%50
n_20, num = num/20, num%20
n_10, num = num/10, num%10
n_5, num = num/5, num%5
n_2, n_1 = num/2, num%2

put_out = str(num_in) + "$ = "
if n_500:
    put_out += str(n_500) + "*500$ + "
if n_200:
    put_out += str(n_200) + "*200$ + "
if n_100:
    put_out += str(n_100) + "*100$ + "
if n_50:
    put_out += str(n_50) + "*50$ + "
if n_20:
    put_out += str(n_20) + "*20$ + "
if n_10:
    put_out += str(n_10) + "*10$ + "
if n_5:
    put_out += str(n_5) + "*5$ + "
if n_2:
    put_out += str(n_2) + "*2$ + "
if n_1:
    put_out += str(n_1) + "*1$ + "

return put_out[:-3]

if name == 'main':
num = input("please input the number:")
out = get_out(num)
print(out)