请问这段python代码为什么总报错？

import matplotlib.pyplot as plt
import numpy as np
import csv
from mpl_toolkits.mplot3d import Axes3D

#定义坐标轴
fig = plt.figure()
ax4 = plt.axes(projection='3d')
#ax = fig.add_subplot(111,projection='3d')  #这种方法也可以画多个子图

filename="D:/data/fujian1.csv"
with open(filename) as f:
    reader=csv.reader(f)
    header_row=next(reader)
    X,Y,Z=[ ],[ ],[ ]
    for row in reader:
        X=int(float(row[1]))
        Xs = np.array(X)
        Y = int(float(row[2]))
        Ys = np.array(Y)
        Z= int(float(row[3]))
        Zs = np.array(Z)
#作图
ax4.plot_surface(Xs,Ys,Zs,alpha=0.3,cmap='winter')     #生成表面， alpha 用于控制透明度
ax4.contour(Xs,Ys,Zs,zdir='Zs', offset=-3,cmap="rainbow")  #生成z方向投影，投到x-y平面
ax4.contour(Xs,Ys,Zs,zdir='Xs', offset=-6,cmap="rainbow")  #生成x方向投影，投到y-z平面
ax4.contour(Xs,Ys,Zs,zdir='Ys', offset=6,cmap="rainbow")   #生成y方向投影，投到x-z平面
#ax4.contourf(Xs,Ys,Zs,zdir='y', offset=6,cmap="rainbow")   #生成y方向投影填充，投到x-z平面，contourf()函数
ax4.set_xlabel('X')
ax4.set_xlim(-300, 300)  #拉开坐标轴范围显示投影
ax4.set_ylabel('Y')
ax4.set_ylim(-300, 300)
ax4.set_zlabel('Z')
ax4.set_zlim(-300, 300)

plt.savefig('figure2.png',dpi=500)
plt.show()

同学你好，散点是无法生成surface的，必须是网格点2D才能生成平面
还有你这句

    for row in reader:
        X=int(float(row[1]))
        Xs = np.array(X)
        Y = int(float(row[2]))
        Ys = np.array(Y)
        Z= int(float(row[3]))
        Zs = np.array(Z)

要改成

    for row in reader:
        X.append(int(float(row[1])))
        Xs = np.array(X)
        Y.append(int(float(row[2])))
        Ys = np.array(Y)
        Z.append(int(float(row[3])))
        Zs = np.array(Z)

这个函数传入的参数有问题，传入的数据需要是二维的
可以参考这个

python - How do I fix " ValueError: Argument Z must be 2-dimensional" error - Stack Overflow I'm trying to plot a 3d surface passes through a set of (X,Y,Z) 3d point and I got raise ValueError("Argument Z must be 2-dimensional.") ax = Axes3D(fig) X = df.index.values Y = np.where(df[' https://stackoverflow.com/questions/58762868/how-do-i-fix-valueerror-argument-z-must-be-2-dimensional-error