编写3个函数实现要求（C语言）

你好，大致程序是这样的

#include <stdio.h>
struct student{
    char id[100];
    float math;
    float physics;
    float chemisty;
    float chinese;
    float gymnastics;
};
// 计算数学分平均 
float math_average(struct student s[], int n){
    int i;
    float ave;
    ave = 0;
    for(i=0; i<n; i++) ave+=s[i].math;
    ave = ave/n;
    return ave;
}

void fail(struct student s[], int n){
    int count, i;
    float ave;
    for(i=0; i<n; i++){
        count = 0;
        if(s[i].math<60)count++;
        if(s[i].physics<60)count++;
        if(s[i].chemisty<60)count++;
        if(s[i].chinese<60)count++;
        if(s[i].gymnastics<60)count++;
        if(count>=2){
            ave = (s[i].math + s[i].physics + s[i].chemisty + s[i].chinese + s[i].gymnastics)/5;
            printf("%s\n",s[i].id);
            printf("math\tphysics\tchemisty\tchinese\tgymnastics\taverage\n");
            printf("%.2f\t%.2f\t%.2f\t\t%.2f\t%.2f\t\t%.2f\n", s[i].math, s[i].physics, s[i].chemisty,s[i].chinese, s[i].gymnastics,ave);
        }
    }
}

void success(struct student s[], int n){
    int count, i;
    float ave;
    for(i=0; i<n; i++){
        count = 0;
        ave = (s[i].math + s[i].physics + s[i].chemisty + s[i].chinese + s[i].gymnastics)/5;
        if(s[i].math>=80)count++;
        if(s[i].physics>=80)count++;
        if(s[i].chemisty>=80)count++;
        if(s[i].chinese>=80)count++;
        if(s[i].gymnastics>=80)count++;
        if(count==5||ave>=85){
            printf("%s\n",s[i].id);
            printf("math\tphysics\tchemisty\tchinese\tgymnastics\taverage\n");
            printf("%.2f\t%.2f\t%.2f\t\t%.2f\t%.2f\t\t%.2f\n", s[i].math, s[i].physics, s[i].chemisty,s[i].chinese, s[i].gymnastics,ave);
        }
    }
}


int main(){
    float a;
    struct student s[10]= {
    {"2021000001",56,78,89,90,45},
    {"2021000002",56,78,89,90,45},
    {"2021000003",56,78,89,90,45},
    {"2021000004",56,78,89,90,45},
    {"2021000005",56,78,89,90,45},
    {"2021000006",56,78,89,90,45},
    {"2021000007",80,81,89,90,85},
    {"2021000008",56,78,89,90,45},
    {"2021000009",59,95,95,90,100},
    {"2021000010",56,78,89,90,45}};
    printf("average math grade:%.2f\n",math_average(s,10));
    printf("\nFail的学生：\n");
    fail(s, 10);
    printf("\nSuccess的学生：\n");
    success(s, 10);
    return 0;
}

 

运行结果截图

百度搜，应该有现成的例子代码。