import re
import requests
r = requests.get('https://www.xcu.edu.cn/mtbd.htm')
print(r.status_code)
pattern = re.compile(
'<li id="(.+?)">(.+?)<a href="(.+?)" target="_blank" title="(.+?)">(.+?)</a>(.+?) (.+?)( new)?</li>',
re.S)
result = pattern.findall(r.content.decode())
for each in result:
print(each[3],each[6])
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