<select id="alarmTypeNumber" parameterType="string" resultType="">
select
alarm_type,count(alarm_type)
from
alarm_infor
where
path like '${value}%'
group by
alarm_type
</select>
标签语句知道,但是不知道如何返回和后台如何接受
可以自定义一个对象,通过自定义resultMap来接受这两个字段
count(alarm_type)
字段设置别名<select id="alarmTypeNumber" parameterType="string" resultType="">
select alarm_type, count(alarm_type) as alarm_type_count
from alarm_infor
where path like '${value}%'
group by alarm_type
</select>
/**
* @author 张玉尧(matrix.zhang@ximalaya.com)
* @version $Id: AlarmTypeCountDO.java, v 0.1 2019年2月21日 上午11:35:35 张玉尧(matrix.zhang@ximalaya.com) Exp $
*/
public class AlarmTypeCountDO {
private String alarmType;
private Long alarmTypeCount;
public String getAlarmType() {
return alarmType;
}
public void setAlarmType(String alarmType) {
this.alarmType = alarmType;
}
public Long getAlarmTypeCount() {
return alarmTypeCount;
}
public void setAlarmTypeCount(Long alarmTypeCount) {
this.alarmTypeCount = alarmTypeCount;
}
}
<select id="alarmTypeNumber" parameterType="string" resultType="包名.AlarmTypeCountDO">
select alarm_type, count(alarm_type) as alarm_type_count
from alarm_infor
where path like '${value}%'
group by alarm_type
</select>
List<Map> alarmTypeNumber(@Param("value") String value);
<select id="alarmTypeNumber" parameterType="java.lang.String" resultType="java.util.Map">
select
alarm_type,count(alarm_type) con
from
alarm_infor
where
path like '${value}%'
group by
alarm_type
</select>
简单的直接返回map即可,Dao 用List 接受