var d = [{"a":"1-1","b":"1-2","c":"1-3"},{"a":"2-1","b":"2-2","c":"2-3"},{"a":"3-1","b":"3-2","c":"3-3"}];
jQuery如何用each()方法遍历它？
$(function(){
var d = [{"a":"1-1","b":"1-2","c":"1-3"},{"a":"2-1","b":"2-2","c":"2-3"},{"a":"3-1","b":"3-2","c":"3-3"}];
$.each(d,function(k,v){
console.log(d[k]);
$.each(d[k],function(k,v){
console.log(v);
})
});
});
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title></title>
</head>
<body>
</body>
<script src="https://cdn.staticfile.org/jquery/1.10.2/jquery.min.js">
</script>
<script>
var d = [{
"a": "1-1",
"b": "1-2",
"c": "1-3"
}, {
"a": "2-1",
"b": "2-2",
"c": "2-3"
}, {
"a": "3-1",
"b": "3-2",
"c": "3-3"
}];
$.each(d, function(index, obj) {
console.log(index, obj)
})
</script>
</html>