#include<iostream>
#include<sstream>
using namespace std;
int inversion(int n){
int a,b,c,d,e;
string str1,str2,str3,str4,str5,str6;
a=n/10000;
b=(n%10000)/1000;
c=((n%10000)%1000)/100;
d=(((n%10000)%1000)%100)/10;
e=(((n%10000)%1000)%100)%10;
str1=a;
str2=b;
str3=c;
str4=d;
str5=e;
str6=str5+str4+str3+str2+str1;
int num=0;
istringstream ss(str6);
ss>>num;
return str6;
}
int main(){
int n=21978;
int a=inversion(n);
cout<<a;
}
}
函数调用,答案不对!
str1=n;
这是什么写法, 整型赋值给字符串?你的目的是啥呢?
完全不知道你要实现什么功能
#include <iostream>
using namespace std;
int inversion(int nn)
{
int n = nn;
int right_digit=0;
do
{
right_digit = 10 * right_digit + n % 10;
n /= 10;
}
while (n != 0);
return right_digit;
}
int main(void)
{
int n=21978;
int a=inversion(n);
cout<<a;
}
供参考:
#include <iostream>
using namespace std;
int inversion(int nn)
{
int digit=0;
while (nn)
{
digit = 10 * digit + nn % 10;
nn /= 10;
}
return digit;
}
int main(void)
{
int n=123456789;
int a=inversion(n);
cout<<a<<endl;
return 0;
}