有没有人知道如何用C++实现双树复小波算法?需要利用双树复小波将图像分为高频子带和低频子带。
双树复小波是一种小波变换,可以将一幅图像分解为多个子带,其中高频子带包含了图像中的细节信息,低频子带包含了图像中的大致轮廓信息。以下是一个简单的双树复小波实现:
#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
// 基础小波函数
double phi(double x) {
double y = 0;
if (x >= -0.5 && x < 0.5) {
y = 1.0;
}
return y;
}
// 基础小波函数的低通滤波器
double lowPassFilter(double x) {
double y = 0.5 * (phi(x / 2.0) + phi((x / 2.0) - 1));
return y;
}
// 基础小波函数的高通滤波器
double highPassFilter(double x) {
double y = 0.5 * (phi(x / 2.0) - phi((x / 2.0) - 1));
return y;
}
// 计算一维离散小波变换
void dwt(vector<double>& signal, vector<double>& lowFreq, vector<double>& highFreq) {
int n = signal.size();
vector<double> temp(n);
int h = n / 2;
for (int i = 0; i < h; i++) {
lowFreq[i] = highFreq[i] = 0.0;
for (int j = 0; j < 2; j++) {
int k = (2 * i) + j;
if (k < n) {
lowFreq[i] += lowPassFilter(k) * signal[k];
highFreq[i] += highPassFilter(k) * signal[k];
}
}
}
}
// 计算二维离散小波变换
void dwt2(vector<vector<double>>& image, vector<vector<double>>& lowFreq, vector<vector<double>>& highFreq) {
int rows = image.size();
int cols = image[0].size();
vector<double> rowSignal(cols), colSignal(rows);
vector<double> rowLowFreq(cols), rowHighFreq(cols);
vector<double> colLowFreq(rows), colHighFreq(rows);
// 水平方向小波变换
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
rowSignal[j] = image[i][j];
}
dwt(rowSignal, rowLowFreq, rowHighFreq);
for (int j = 0; j < cols; j++) {
lowFreq[i][j] = rowLowFreq[j];
highFreq[i][j] = rowHighFreq[j];
}
}
// 垂直方向小波变换
for (int j = 0; j < cols; j++) {
for (int i = 0; i < rows; i++) {
colSignal[i] = lowFreq[i][j];
}
dwt(colSignal, colLowFreq, colHighFreq);
for (int i = 0; i < rows;