Expecting value:line1column1(char 0)

爬虫时进行Response中的json数据提取，将返回内容转化为dic类型时报 Expecting value: line 1 column 1 (char 0)错。

问题代码如下：

import requests
import json
import jsonpath


url = "http://www.zgei.com/?name=%E6%88%91%E6%83%B3%E8%A6%81&type=qq"

r = requests.get(url=url,timeout=3)

if r.content != None:
    data = json.loads(r.content.decode('utf-8-sig'))
    #这里将解码成utf-8-sig 是因为会报unexpected utf-8 bom (decode using utf-8-sig) line 1 column 1 (char 0)错误

完整报错代码如下：

Traceback (most recent call last):
  File "D:/pythonProject/Music_Download/1000.py", line 10, in <module>
    data = json.loads(r.content.decode('utf-8-sig'))
  File "D:\Python\lib\json\__init__.py", line 357, in loads
    return _default_decoder.decode(s)
  File "D:\Python\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "D:\Python\lib\json\decoder.py", line 355, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

json.loads()报错
查了好多种方法都还是报这个错，有说url不对应，改了也不好使，实在不知道那里的问题！！

你访问的网址返回的是html代码，不是json格式字符串当然出错了。内容是post请求的http://www.zgei.com/接口发送参数。
有帮助麻烦点个采纳【本回答右上角】，谢谢~~

示例代码如下

import requests
headers={
"Referer": "http://www.zgei.com/?name=%E6%88%91%E6%83%B3%E8%A6%81&type=qq",
"X-Requested-With":"XMLHttpRequest",
"Referrer Policy":"strict-origin-when-cross-origin"
};
data={"input":"我想要","filter":"name","type":"qq","page":1};
r=requests.post("http://www.zgei.com/",headers=headers,data=data)
data=r.json()
if data["code"]==200:
    for song in data["data"]:
        print(song["title"]+"--"+song["author"])
else:
    print(data)

把json数据打印出来看看，应该是不符合json规范的字符串。