统计1到a之间大于10的奇数的个数,a为输入的数值
#include <stdio.h>
int main()
{
int a,sum=0;
scanf("%d",&a);
for (int i = 1; i <= a;i+=2)
sum += (i>10)?1:0;
printf("sum=%d\n", sum);
return 0;
}
不用循环,不用if,不行骂我,供参考
#include <stdio.h>
int main()
{
int n,z=0;
scanf("%d",&n);
z =(n+1-10)/2
printf("total: %d\n", z);
return 0;
}
#include <stdio.h>
int main()
{
int a,sum=0;int i = 11;
scanf("%d",&a);
for (;i <= a;i++)
{
if(i%2!=0)sum++;
}
printf("sum=%d\n", sum);
return 0;
}