这个ATM机的小程序里密码错误和case0退出为什么都会跳到，用户名不存这个else里面去
const as = require('readline-sync');
let accunt = [`z3`, 123, 100, `l4`, 456, 200, `w5`, 789, 300,];
let count = 3
let state = true;
while (count >= 3 && state) {
count--;
console.log(`请输入账号`)
let inputName = as.question()
for (let index = 0; index < accunt.length; index++) {
if (inputName == accunt[index] && (index % 3 == 0 || index == 0)) {
console.log(`请输入密码`)
let inputPwd = as.question();
if (inputPwd == accunt[index + 1]) {
console.log(`登录成功`)
while (
state
) {
console.log(`请选择 1、查询余额 2、存款 3、取出 0、退出`);
let inputNum = as.question() - 0;
switch (inputNum) {
case 0:
console.log(`see you`)
state = false;
break;
case 1:
console.log(`您当前余额为${accunt[index + 2]}`);
break;
case 2:
console.log(`请输入存入金额`);
let inputMoney = as.question() - 0;
accunt[index + 2] += inputMoney;
console.log(`存入成功，您当前的余额是${accunt[index + 2]}`);
break;
case 3:
console.log(`请输入需要取出的金额`);
let drawMoney = as.question() - 0;
if (drawMoney > accunt[index + 2]) {
console.log(`您的余额不足`);
}
else {
accunt[index + 2] = accunt[index + 2] - drawMoney;
console.log(`取出成功，您当前余数为${accunt[index + 2]}`);
}
break;
}
}
} else if (index == accunt.length - 1) {
(`您输入的密码有误，请重新输入。您当前还可以输入${count}次`)
}
}
else if (count == 0) {
console.log(`登录失败，您的账户已经被冻结`);
}
else if (index == accunt.length - 1) {
console.log(`您输入的用户名${inputName}不存在，请重新输入。您当前还可以输入${count}次`)
}
}
}
你代码业务逻辑有点乱，你把判断if else层级分好。也可以用debugger调试一下。