代码:
A = [1 2 3 4 5 6 5 4 3 2 1];
n = 3;
for ii = 1:length(A)+1-n
B(ii,:) = A(ii:ii+n-1);
end
B
结果:
B =
1 2 3
2 3 4
3 4 5
4 5 6
5 6 5
6 5 4
5 4 3
4 3 2
3 2 1