JAVA基础问题判断正误

判断正误 1、The statement Integer.parseInt(“123abc”) is valid syntactically, which will produce an exception when run. 2、You are permitted to use an interface as a data type to declare a variable.When running 3、the statement System.out.println(“x+y=” + 13 + 25), you will get the result x+y=38.

1、对的，Integer.parseInt("123abc");在运行中会产生异常。
2、对的，允许您使用接口作为数据类型来声明变量
3、错的，System.out.println("x+y="+13+25); 输出结果为：x+y=1325