词频统计～～～～～！！

 把内容替换一下就行了

hamletText = "asd fasd asd a asd as as  f  as da asd "
words = hamletText.split()
counts = {}
for word in words:
    counts[word] = counts.get(word,0) + 1
items = list(counts.items())
items.sort(key = lambda x:x[1],reverse = True)

for i in range(len(items)):
    word,count = items[i]
    print("{0:<10}{1:>5}".format(word,count))

https://blog.csdn.net/codejas/article/details/80356544?utm_source=app&app_version=4.9.3&code=app_1562916241&uLinkId=usr1mkqgl919blen

推荐这篇文章，很详细，希望可以帮助你