统计句子 Whatever is worth doing is worth doing well 中字母e和字母o出现的次数
var arr = 'Whatever is worth doing is worth doing well';
var obj = {};
for (var i = 0; i < arr.length; i++) {
var key = arr[i];
if (obj[key]) {
obj[key]++;
} else {
obj[key] = 1;
}
}
console.log(obj['e'], obj['o']);
望采纳
运行结果: