用Python实现这个函数的结果，利用步长计算

import math
s={}
for step in range(1,100):
    a = 1.15
    x = 1   
    for i in range(1,step,1):
        x+=a**i*1/math.factorial(i)
    print(x)
    error=abs(x-math.e**a)
    s[step]=error
print(s)
st = sorted(s.items(), key=lambda x: x[1])
print(f'从1开始，循环到{st[0][0]}，即可达最优值')

循环到第19步时就与math.e计算结果相同

def fun(x):
    import math
    a, b, c, n = 1, 1, 1, 1
    while n <= 100:
        a = a * x / n
        b = b + a
        n += 1
        if a < 0.0001:
            break
    print(b)
x = float(input())
fun(x)