描述：不是获得当前url路径，是调用其他的url
目前为止还不知道LZ到底要的是什么，不管了，再来个Ajax的，很简单的demo。
把两个jsp放到Web应用里面，要放在同一个目录下，打开ajaxGetPost.jsp这个页面，ajaxGetPost.jsp页面通过Ajax访问ajaxGetPostUse.jsp页面。
[code="jsp"]<%@ page language="java" pageEncoding="GBK"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
简单的通过URLConnection：
[code="java"]import java.net.*;
import java.io.*;
import java.util.Date;
public class URLConnectionDemo {
public static void main(String[] args) throws IOException {
URL url = new URL("http://127.0.0.1:8080/cfStruts2Ex2/");
URLConnection urlConn = url.openConnection();
System.out.println("Date: " + new Date(urlConn.getDate()));
System.out.println("Content-Type: " + urlConn.getContentType());
int length = urlConn.getContentLength();
System.out.println("Content-Lentgth: " + length);
if (length > 0) {
System.out.println("========== Content ==========");
InputStream input = urlConn.getInputStream();
int i = length;
int c;
while ((c = input.read()) != -1 && --i > 0) {
System.out.print((char) c);
}
input.close();
} else {
System.out.println("No Content.");
}
}
}[/code]
或者可以用HttpClient：
[code="java"]import java.io.IOException;
import org.apache.commons.httpclient.DefaultHttpMethodRetryHandler;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpException;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.methods.GetMethod;
import org.apache.commons.httpclient.params.HttpMethodParams;
public class HttpClientTutorial {
private static String url = "http://www.baidu.com/";
public static void main(String[] args) {
// Create an instance of HttpClient.
HttpClient client = new HttpClient();
// Create a method instance.
GetMethod method = new GetMethod(url);
// Provide custom retry handler is necessary
method.getParams().setParameter(HttpMethodParams.RETRY_HANDLER,
new DefaultHttpMethodRetryHandler(3, false));
try {
// Execute the method.
int statusCode = client.executeMethod(method);
if (statusCode != HttpStatus.SC_OK) {
System.err.println("Method failed: " + method.getStatusLine());
}
// Read the response body.
byte[] responseBody = method.getResponseBody();
// Deal with the response.
// Use caution: ensure correct character encoding and is not binary
// data
System.out.println(new String(responseBody, "GBK"));
} catch (HttpException e) {
System.err.println("Fatal protocol violation: " + e.getMessage());
e.printStackTrace();
} catch (IOException e) {
System.err.println("Fatal transport error: " + e.getMessage());
e.printStackTrace();
} finally {
// Release the connection.
method.releaseConnection();
}
}
}[/code]
如果需要鉴权，那就只能用HttpClient，而且要加鉴权：
[code="java"]String newUrl = "http://10.167.129.108/fnst_travel/BasicInformation.do";
NameValuePair[] paramPairs = new NameValuePair[] {
new NameValuePair("registrationPersonNum", "1"),
new NameValuePair("myName", "Chen Feng"),
new NameValuePair("myNameIDnumber", "123321123321"),
new NameValuePair("myNamePhonenumber", "15951836132") };
PostMethod method = new PostMethod(newUrl);
method.setRequestBody(paramPairs);
int statusCode = client.executeMethod(method);[/code]
你可以使用ajax得到返回的内容，然后再解析得到的内容就可以了
这个不是只要在第一个JSP页面ONload的时候用AJAX发起一个请求就可以了吗？
描述：不是获得当前url路径，是调用其他的url
1、如使用URLConnection 或 httpclient等工具抓取数据