用ascii判断,字母>='a' and 字母<='z‘的保留就可以了。
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str[100], *p = str, *q = str, cnt = 0;
scanf("%s", str);
while (*p != '\0') {
if (*p >= 'a' && *p <= 'z') {
*q = *p;
cnt++;
q++;
}
p++;
}
*q = '\0';
printf("新字符串:%s\n", str);
printf("字母个数:%d\n", cnt);
system("pause");
return 0;
}
void fun(char *s)
{
char *p = new char[strlen(s)+1];
char *ps = s;
char *ps2 = p;
while (*ps != '\0')
{
if (*ps >= 'a' && *ps <= 'z')
{
*ps2++ = *ps;
}
ps++;
}
*ps2 = '\0';
strcpy(s, p);
delete [] p;
}
您好,我是有问必答小助手,您的问题已经有小伙伴解答了,您看下是否解决,可以追评进行沟通哦~
如果有您比较满意的答案 / 帮您提供解决思路的答案,可以点击【采纳】按钮,给回答的小伙伴一些鼓励哦~~
ps:问答VIP仅需29元,即可享受5次/月 有问必答服务,了解详情>>>https://vip.csdn.net/askvip?utm_source=1146287632