SQL Server怎么实现只获取指定小时的第一条记录

数据库表a:电表记录,NUM为表号

NUM                  D_DATE                           D_VALUE             ADDR

10001       2021-05-01 00:04:26.000            1459.3                302室

10001       2021-05-01 00:05:32.000            1459.3                302室

10001       2021-05-01 00:30:00.000            1459.3                302室

10002       2021-05-01 00:04:26.000            237.44                301室

10002       2021-05-01 00:05:32.000            237.45                301室

10003       2021-05-01 00:04:32.000            1525.25              303室

10003       2021-05-01 00:44:39.000            1525.35              303室

......

现在想要将每个电表在0时,8时,11时,13时,19时,21时,22时,23时的第一条记录存放在表b。

这样写就好呀:select num,d_date,d_value,addr into b from a where d_date in 

(select d_date from (select number() over(group by year(d_date),month(d_date,day(d_date),hour(d_date) order by d_date)  as myseqnum,* from a) as tmptable1 where myseqnum=1) and hour(d_date) in (0,8,11,13,19,21,22,23) 

刚才写错了,现在重写如下:

select * from 
     (select row_number() over(partition by year(d_date),month(d_date),day(d_date),datepart(hour,d_date) order by d_date)  as myseqnum, * from a)
      as tmptable1 
      where myseqnum=1 and datepart(hour,d_date) in (0,8,11,13,19,21,22,23)