python编程求解答

def hu(n1,n2):

    if n1 < n2:

        n1,n2 = n2,n1

    while n2:

        n1,n2 = n2,n1%n2

    return n1

def min(n1,n2):

    if n1 < n2:

        n1,n2 = n2,n1

    x = n1 * n2

    while n2:

        n1,n2 = n2,n1%n2

    return x//n1

a = 5

b = 10

print(hu(a,b))

print(min(a,b))