班级表
SELECT
classno,
course,
avgg,
count( studentno ) AS shuliang
FROM
(
SELECT
a.classno,
a.course,
a.gradee,
a.studentno,
p.avgg
FROM
class a
JOIN ( SELECT avg( gradee ) AS avgg, classno, course FROM class b GROUP BY course, classno ) p ON a.classno = p.classno
AND a.course = p.course
) m
GROUP BY
course,
gradee
having
gradee < avgg
真够复杂的
select count(1)as shuliang,classno,course
from tableName
where grade < avg(grade)
group by classnno,course
tableName改一下,你试试
。。。你这个,
select count(1)as shuliang,classno,course
from class a
where gradee < (select avg(gradee) from class group by classno,course)
你测一下,我在多弄几组数据测一测