求大佬帮忙看一下，谢谢了！ 程序是网上摘的，但是网课用的也是这个例子，就运行不出来，会显示： f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0. 原因: 已达到最大递归限制 5000。 该怎么解决啊？ function iprime =Gllshort(t,i) f=50.; w=2.*pi*f; d=0.; d=d*pi/180.; theta=w*t+d; % Parameters of a 500 MVA, 30 kV Synchronous Machine Ld = 0.0072; Lq = 0.0070; L0=0.0010; LF = 2.500; LD = 0.0068; LQ = 0.0016; MF = 0.100; MD = 0.0054; MQ = 0.0026; MR = 0.1250; r = 0.002; rF = 0.4000; rD = 0.015; rQ = 0.0150; VF = 400; % dc field voltage V = [0; 0; 0; VF; 0; 0]; % Voltage column vector K=3/2.; RT2=sqrt(2.0); R=[r 0 0 0 0 0 0 r 0 0 0 0 0 0 r 0 0 0 0 0 0 rF 0 0 0 0 0 0 rD 0 0 0 0 0 0 rQ]; L=[Ld 0 0 MF MD 0 0 Lq 0 0 0 MQ 0 0 L0 0 0 0 K*MF 0 0 LF MR 0 K*MD 0 0 MR LD 0 0 K*MQ 0 0 0 LQ]; WW=[0 -w 0 0 0 0 w 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]; Li=inv(L); iprime=Li*V - Li*(WW*L+R)*i; VF = 400; rF = 0.4; iF0 = VF/rF; f = 50; w = 2.*pi*f; pi2=2.*pi/3; d = 0; d = d*pi/180; t0 = 0 ; tfinal = 0.80; i0 = [0; 0; 0; iF0; 0; 0;]; % 电流初值 tspan = [t0, tfinal]; [t,i] = ode45('Gllshort', tspan, i0); % id,iq,i0 = Armature current iF=Field current id = i(:,1); iq = i(:,2); i0 = i(:,3); iF = i(:,4); iD = i(:,5); iQ = i(:,6);%iF为励磁电流 %current dq0 to current abc nn=length(id); for kk=1:nn, tt=t(kk);thetaa=w*tt;thetab=thetaa-pi2;thetac=thetaa+pi2; ia(kk)=cos(thetaa)*id(kk)-sin(thetaa)*iq(kk)+i0(kk); ib(kk)=cos(thetab)*id(kk)-sin(thetab)*iq(kk)+i0(kk); ic(kk)=cos(thetac)*id(kk)-sin(thetac)*iq(kk)+i0(kk); end figure(1), plot(t,ia), xlabel('t, sec'), ylabel('ia, A'), grid title(['three phase short circuit ia, ','delta = ', num2str(d)]) figure(2), plot(t,iF), xlabel('t, sec'), ylabel('iF, A'), grid title(['Line-line short circuit iF, ','delta = ',num2str(d)])
function iprime =Gllshort(t,i) f=50.; w=2.*pi*f; d=0.; d=d*pi/180.; theta=w*t+d; % Parameters of a 500 MVA, 30 kV Synchronous Machine Ld = 0.0072; Lq = 0.0070; L0=0.0010; LF = 2.500; LD = 0.0068; LQ = 0.0016; MF = 0.100; MD = 0.0054; MQ = 0.0026; MR = 0.1250; r = 0.002; rF = 0.4000; rD = 0.015; rQ = 0.0150; VF = 400; % dc field voltage V = [0; 0; 0; VF; 0; 0]; % Voltage column vector K=3/2.; RT2=sqrt(2.0); R=[r 0 0 0 0 0 0 r 0 0 0 0 0 0 r 0 0 0 0 0 0 rF 0 0 0 0 0 0 rD 0 0 0 0 0 0 rQ]; L=[Ld 0 0 MF MD 0 0 Lq 0 0 0 MQ 0 0 L0 0 0 0 K*MF 0 0 LF MR 0 K*MD 0 0 MR LD 0 0 K*MQ 0 0 0 LQ]; WW=[0 -w 0 0 0 0 w 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]; Li=inv(L); iprime=Li*V - Li*(WW*L+R)*i; VF = 400; rF = 0.4; iF0 = VF/rF; f = 50; w = 2.*pi*f; pi2=2.*pi/3; d = 0; d = d*pi/180; t0 = 0 ; tfinal = 0.80; i0 = [0; 0; 0; iF0; 0; 0;]; % 电流初值 tspan = [t0, tfinal]; [t,i] = ode45('Gllshort', tspan, i0); % id,iq,i0 = Armature current iF=Field current id = i(:,1); iq = i(:,2); i0 = i(:,3); iF = i(:,4); iD = i(:,5); iQ = i(:,6);%iF为励磁电流 %current dq0 to current abc nn=length(id); for kk=1:nn, tt=t(kk);thetaa=w*tt;thetab=thetaa-pi2;thetac=thetaa+pi2; ia(kk)=cos(thetaa)*id(kk)-sin(thetaa)*iq(kk)+i0(kk); ib(kk)=cos(thetab)*id(kk)-sin(thetab)*iq(kk)+i0(kk); ic(kk)=cos(thetac)*id(kk)-sin(thetac)*iq(kk)+i0(kk); end figure(1), plot(t,ia), xlabel('t, sec'), ylabel('ia, A'), grid title(['three phase short circuit ia, ','delta = ', num2str(d)]) figure(2), plot(t,iF), xlabel('t, sec'), ylabel('iF, A'), grid title(['Line-line short circuit iF, ','delta = ',num2str(d)])