求大神带看看这道题 求求了

3.猜数游戏 (1)游戏开始，提示"Ganestart!"，并随机产生一个1^90 的数让用户猜，用户基础分为10分，猜错一次扣1分。 (2)如果用户猪错，则提示“Too big! ”还是“Too small! (3)如果猜了10次均未猜中，提示"You Failed! The aumber is r”,r为目标数字。 (4)如果猜对，则提示"Congratulation! Your gessind Lerel is S/A/B/C/D/E" ，其中level由用户剩余分数决定。 S: 10分A:9分B:8分C:7分D:6分E: 1^5分

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void main()
{
    int ret = 0;
    int i = 0;
	int rnd = 0;
	int level = 10;
	srand((unsigned int)time(NULL));
	ret = rand()%90;
	printf("Ganestart!\n");
	while(1)
	{
		printf("请输入一个数:");
		scanf("%d",&rnd);
		if(rnd>ret){
			printf("Too big! \n");	
		}else if(rnd<ret){
			printf("Too small! \n");	
		}else{
			break;
		}
		level--;
		if(level<=0){
			printf("You Failed! The aumber is r");
			exit(0);	
		}
	}
	switch(level){
		case 10:
			printf("Congratulation! Your gessind Lerel is S");
			break;
		case 9:
			printf("Congratulation! Your gessind Lerel is A");
			break;
		case 8:
			printf("Congratulation! Your gessind Lerel is B");
			break;
		case 7:
			printf("Congratulation! Your gessind Lerel is C");
			break;
		case 6:
			printf("Congratulation! Your gessind Lerel is D");
			break;
		case 5:
		case 4:
		case 3:
		case 2:
		case 1:
		case 0:
			printf("Congratulation! Your gessind Lerel is E");
			break;	
	}
	
	return 0;
}

用二分法的话，根本不需要10次肯定就能猜中了啊

作业要自己做。实在不会再上来求助。这代码百度都烂大街了。

你是哪里不会，先写自己会部分，有不会的再来问

#include <stdlib.h>
#include<time.h>
int main(){
   
	printf("game start!\n");

	srand((unsigned)time(NULL));//选取种子文件
	int score = 10;
	int n = rand()%90;
	int m = 0;
	while(1)
	{
		printf("请输入你猜测的数字：");
		scanf_s("%d",&m);
		if(m == n)
		{
			char ch;
			switch(score)
			{
			case 10:
				ch = 'S';
				break;
			case 9:
				ch = 'A';
				break;
			case 8:
				ch = 'B';
				break;
			case 7:
				ch = 'C';
				break;
			case 6:
				ch = 'D';
				break;
			default:
				ch = 'E';
				break;
			}
			printf("Congratulation! Your gessind Lerel is %c",ch);
			break;
		}
		else if(m>n)
		{
			printf("Too big!\n");
			score--;
		}
		else
		{
			printf("Too small!\n");
			score--;
		}
	}

	return 0;
}

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void main()
{
    int ret = 0;
    int i = 0;
	int rnd = 0;
	int level = 10;
	srand((unsigned int)time(NULL));
	ret = rand()%90;
	printf("Ganestart!\n");
	while(1)
	{
		printf("请输入一个数:");
		scanf("%d",&rnd);
		if(rnd>ret){
			printf("Too big! \n");	
		}else if(rnd<ret){
			printf("Too small! \n");	
		}else{
			break;
		}
		level--;
	}
	switch(level){
		case 10:
			printf("Congratulation! Your gessind Lerel is S");
			break;
		case 9:
			printf("Congratulation! Your gessind Lerel is A");
			break;
		case 8:
			printf("Congratulation! Your gessind Lerel is B");
			break;
		case 7:
			printf("Congratulation! Your gessind Lerel is C");
			break;
		case 6:
			printf("Congratulation! Your gessind Lerel is D");
			break;
		case 5:
		case 4:
		case 3:
		case 2:
		case 1:
		case 0:
			printf("Congratulation! Your gessind Lerel is E");
			break;	
	}
	
	return 0;
}

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